Set date and time - MonthDayhoursMinutesYear.Seconds

date 041217002007.00

Search files created or changed within 10 days

find /usr/bin -type f -mtime -10

Some date finding commands..

$ date
Mon Mar 10 23:52:08 IST 2008
$ cal
     March 2008
Su Mo Tu We Th Fr Sa
                   1
 2  3  4  5  6  7  8
 9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25 26 27 28 29
30 31

Create the MySQL format date(YYYY-MM-DD) using the date command

date +%Y-%m-%d

This function will find the difference between two given times. Does PHP already have a native function for that?

//The difference between 2 given time
function dateDifference($day_1,$day_2) {
	$diff = strtotime($day_1) - strtotime($day_2);

	$sec   = $diff % 60;
	$diff  = intval($diff / 60);
	$min   = $diff % 60;
	$diff  = intval($diff / 60);
	$hours = $diff % 24;
	$days  = intval($diff / 24);

	return array($sec,$min,$hours,$days);
}

If you just want the day difference…

$diff = strtotime($day_1) - strtotime($day_2) + 1; //Find the number of seconds
$day_difference = ceil($diff / (60*60*24)) ;  //Find how many days that is

This can be done using the DATEDIFF function in MySQL 5

[tags]php,code,date,difference,time[/tags]

Javascript code for finding the fourth sunday in any given month.

function findFourthSunday(year,month) {
	var fourth_sunday = 0;
	var sunday_count = 0;
	//There is a really cool solution for this
	//forth_sunday = 29 - first_day_of_month
	//But the problem is if the first of month is a sunday(first_day_of_month == 0), then there will be a bug. Found the bug in April 2007 
	for(var i=1;i<31;i++) {
		var a_day = new Date(year,month,i);
		if(a_day.getDay() == 0) sunday_count++;//'0' means sunday - 1 for monday, etc.

		if(sunday_count == 4) {
			fourth_sunday = i;
			break;
		}
	}
	return fourth_sunday;
}
function init() {
	var month_names = new Array("January","February","March","April","May","June","July","Augest","September","October","November","December");
	var first_day = ""
	var today = new Date();
	var year = today.getYear();
	year = (year > 2000) ? year : year + 1900;
	var month = today.getMonth();

	var fourth_sunday = findFourthSunday(year,month);
	if(today.getDate() > fourth_sunday) {
		month ++;
		fourth_sunday = findFourthSunday(year,month);
	} else if(today.getDate() == fourth_sunday) {
		fourth_sunday = "Today - " + fourth_sunday;
	}
	var date = fourth_sunday + " " + month_names[month] + ", " + year;
	alert(date);
}
window.onload=init;

[tags]javascript,fourth,sunday,calender,month,date,day,code[/tags]